(4x^2-5)=(3x^2+7)

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Solution for (4x^2-5)=(3x^2+7) equation:


Simplifying
(4x2 + -5) = (3x2 + 7)

Reorder the terms:
(-5 + 4x2) = (3x2 + 7)

Remove parenthesis around (-5 + 4x2)
-5 + 4x2 = (3x2 + 7)

Reorder the terms:
-5 + 4x2 = (7 + 3x2)

Remove parenthesis around (7 + 3x2)
-5 + 4x2 = 7 + 3x2

Solving
-5 + 4x2 = 7 + 3x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x2' to each side of the equation.
-5 + 4x2 + -3x2 = 7 + 3x2 + -3x2

Combine like terms: 4x2 + -3x2 = 1x2
-5 + 1x2 = 7 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-5 + 1x2 = 7 + 0
-5 + 1x2 = 7

Add '5' to each side of the equation.
-5 + 5 + 1x2 = 7 + 5

Combine like terms: -5 + 5 = 0
0 + 1x2 = 7 + 5
1x2 = 7 + 5

Combine like terms: 7 + 5 = 12
1x2 = 12

Divide each side by '1'.
x2 = 12

Simplifying
x2 = 12

Take the square root of each side:
x = {-3.464101615, 3.464101615}

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